document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141712>Question 141712</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle centered at the origin has a radius of 6sqrt2. If the point(6sqrt2,0) is rotated 45 degrees clockwise, determine the coordinates of the new point. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103250 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = rcos(theta)<BR>\n" );
document.write( "y = rsin(theta)<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "Your problem:<BR>\n" );
document.write( "x = 6sqrt(2)cos(-45) = 6sqrt(2)[1/sqrt(2)] = 6<BR>\n" );
document.write( "y = 6sqrt(2)sin(-45) = 6sqrt(2)[-1/sqrt(2)] = = -6<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );