document.write( "Question 21426: how do you find three consecutive integers whose sum is 171 \n" ); document.write( "

Algebra.Com's Answer #10325 by elima(1433) $\"\"$ $\"About$

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three consecutive integers whose sum is 171
\n" ); document.write( "Let x be the first integer,
\n" ); document.write( "now the next consecutive integer would be right after x, right?
\n" ); document.write( "so we have;
\n" ); document.write( "x+1
\n" ); document.write( "the third integer would be 2 away from x, right?
\n" ); document.write( "x+2
\n" ); document.write( "So our three consecutive integers would be;
\n" ); document.write( "x, x+1, x+2
\n" ); document.write( "so we have;
\n" ); document.write( "x+x+1+x+2=171
\n" ); document.write( "Add like terms;
\n" ); document.write( "3x+3=171
\n" ); document.write( "subtract 3 from both sides;
\n" ); document.write( "3x+3-3=171-3
\n" ); document.write( "3x=168
\n" ); document.write( "divide each side by 3;
\n" ); document.write( " $\"3x%2F3\"$ = $\"168%2F3\"$
\n" ); document.write( "x=56
\n" ); document.write( "So our first integer would be 56,
\n" ); document.write( "so then our next two would be;
\n" ); document.write( "57,58
\n" ); document.write( "=) \n" ); document.write( "

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