document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141714>Question 141714</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A point P having coordinates (-0.6561,-0.7547), lies on the terminal arm of an angle theta in standard position on a unit circle. Sketch this situation and determine the value of theta in degrees. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103247 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A point P having coordinates (-0.6561,-0.7547), lies on the terminal arm of an angle theta in standard position on a unit circle. Sketch this situation and determine the value of theta in degrees.<BR>\n" );
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document.write( "The point is in the 3rd quadrant.<BR>\n" );
document.write( "The reference angle is tan^-1[-0.7547/-0.6561] = 48.997 degrees<BR>\n" );
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document.write( "Therefore theta = 180 + 48.997 = 228.997 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );