document.write( "Question 141699: Trains A and B are travelling at the same direction on paralell tracks. Train A is travelling at 40 miles per hour and Train B is travelling at 60 miles per hour. Train A passes a station at 3:25 AM. If train B passes the same station at 3:37AM. At what time will train B catch up with train A??
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document.write( "How do I figure this one out?? \n" );
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Algebra.Com's Answer #103245 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Trains A and B are traveling at the same direction on parallel tracks. \n" ); document.write( "Train A is traveling at 40 miles per hour and \n" ); document.write( "Train B is travellng at 60 miles per hour. \n" ); document.write( "Train A passes a station at 3:25 AM. \n" ); document.write( "If train B passes the same station at 3:37AM. At what time will train B catch up with train A??\r \n" ); document.write( "\n" ); document.write( "------------------- \n" ); document.write( "The problem starts at the station. \n" ); document.write( "B leaves the station 12 minutes, or (1/5) hr., after A. \n" ); document.write( "When B catches A they are the same distance from the station. \n" ); document.write( "------------------ \n" ); document.write( "A DATA; \n" ); document.write( "rate = 40 mph ; time = x hrs ; distance = 40x miles \n" ); document.write( "-------------------- \n" ); document.write( "B DATA: \n" ); document.write( "rate = 60 mph ; time = (x-(1/5)) ; distance = 60(x-(1/5)) = 60x-12 miles \n" ); document.write( "------------------ \n" ); document.write( "EQUATION: \n" ); document.write( "40x = 60x-12 \n" ); document.write( "20x = 12 \n" ); document.write( "x = 3/5 hr = 36 minutes \n" ); document.write( "3:25 + 36 = 4:01 AM (time A catches up to B) \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |