document.write( "Question 141581: Tutors I have the following problem: Use substitution to determine that -4,2,1are zeros of f(x)=x^3+3x^2-4x\r
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Algebra.Com's Answer #103203 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"f%28x%29=x%5E3%2B3x%5E2-4x\"$
\n" ); document.write( " $\"f%28-4%29=%28-4%29%5E3%2B3%28-4%29%5E2-4%28-4%29\"$
\n" ); document.write( " $\"f%28-4%29=-64%2B48%2B16\"$
\n" ); document.write( " $\"f%28-4%29=0\"$
\n" ); document.write( "x=-4 is a zero of f(x).
\n" ); document.write( " $\"f%282%29=2%5E3%2B3%282%29%5E2-4%282%29\"$
\n" ); document.write( " $\"f%282%29=8%2B12-8\"$
\n" ); document.write( " $\"f%282%29=12\"$
\n" ); document.write( "x=2 is not a zero of f(x).
\n" ); document.write( " $\"f%281%29=1%5E3%2B3%281%29%5E2-4%281%29\"$
\n" ); document.write( " $\"f%281%29=1%2B3-4\"$
\n" ); document.write( " $\"f%281%29=0\"$
\n" ); document.write( "x=1 is a zero of f(x).
\n" ); document.write( " \n" ); document.write( "

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