document.write( "Question 141626: the length and width of a rectangle are given by consecutive integers. the area of the rectangle is 90cm^2. find the length of a diangonal of the rectangle \n" ); document.write( "

Algebra.Com's Answer #103173 by solver91311(24713) $\"\"$ $\"About$

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If the width is x, then the length must be x + 1 because the dimensions are consectutive integers. The given area is 90, so $\"x%28x%2B1%29=90\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%28x%2B1%29=90\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2Bx-90=0\"$ \r
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\n" ); document.write( "\n" ); document.write( "Solve the quadratic excluding the extraneous negative root to get the width, add 1 to get the length, and then use the Pythagorean Theorem to calculate the length of the diagonal. You should probably leave your answer in terms of a radical, but if you do choose to express the numerical approximation, it should be rounded to the nearest centimeter. That's because your least precise given measurement -- the area -- was given to the nearest square centimeter. \n" ); document.write( "

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