document.write( "Question 141629: A solution of 68% fertilizer is to be mixed with a solution of 32% fertilizer to form 108 liters of a 40% solution. How many liters of the 68% solution must be used? \n" ); document.write( "
Algebra.Com's Answer #103166 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .68X+.32(108-X)=.40*108 \n" ); document.write( ".68X+34.56-.32X=43.2 \n" ); document.write( ".36X=43.2-34.56 \n" ); document.write( ".36X=8.64 \n" ); document.write( "X=8.64/.36 \n" ); document.write( "X=24 LITERS OF 68% SOLUTION IS REQUIRED. \n" ); document.write( "PROOF: \n" ); document.write( ".68*24+.32(108-24)=43.2 \n" ); document.write( "16.32+.32*84=43.2 \n" ); document.write( "16.32+26.88=43.2 \n" ); document.write( "43.2=43.2 \n" ); document.write( " |