document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141569>Question 141569</A>: <I><SPAN STYLE=\"word-break: break-all;\"> problem:    The two numbers whose sum is -10 and product is 24 are? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103163 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103163\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x and y the numbers then<BR>\n" );
document.write( "x+y = -10<BR>\n" );
document.write( "xy=24\r<BR>\n" );
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document.write( "y=-x-10\r<BR>\n" );
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document.write( "x(-x-10)=24<BR>\n" );
document.write( "-x^2-10x-24=0\r<BR>\n" );
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document.write( "x= (10+sqrt(100-96))/-2 or x= (10-sqrt(100-96))/-2<BR>\n" );
document.write( "then x=-6 or x=-4<BR>\n" );
document.write( "then y=-4 or y=-6\r<BR>\n" );
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document.write( "Answer: Numbers are -6 and -4 </SPAN>\n" );
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