document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141571>Question 141571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Problem:  Solve by factoring... 7X(X-1)=1-X </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103146 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103146\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 7X(X-1)=1-X<BR>\n" );
document.write( "7x^2-7x=1-x<BR>\n" );
document.write( "7x^2-6x-1=0<BR>\n" );
document.write( "7x^2-7x+x-1=0 Multiply the 1st and 3rd coefficients. (7*-1=-7) What 2 factors of -7 add up to the 2nd coefficient (-7,+1).<BR>\n" );
document.write( "7x(x-1)+(x-1)=0<BR>\n" );
document.write( "(7x+1)(x-1)=0 Factoring by grouping<BR>\n" );
document.write( "7x=-1 x=-1/7<BR>\n" );
document.write( "x=1<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );