document.write( "Question 141559: How do I solve?\r
\n" ); document.write( "\n" ); document.write( "A person traveled 120 miles in one direction. The return trip was accomplished at double the speed and took three hours less time. Find the speed going.
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Algebra.Com's Answer #103145 by ankor@dixie-net.com(22740)\"\" \"About 
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How do I solve?
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\n" ); document.write( "Let x = speed going
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\n" ); document.write( "2x = return speed
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\n" ); document.write( "A person traveled 120 miles in one direction. The return trip was accomplished at double the speed and took three hours less time. Find the speed going.
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\n" ); document.write( "Write a time equation: Time = dist/speed
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\n" ); document.write( "Going time = return time + 3 hrs
\n" ); document.write( "\"120%2Fx\" = \"120%2F%282x%29\" + 3
\n" ); document.write( "Multiply equation by 2x to get rid of the denominator:
\n" ); document.write( "2(120) = 120 + 3(2x)
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\n" ); document.write( "240 = 120 + 6x
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\n" ); document.write( "240 - 120 = 6x
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\n" ); document.write( "120 = 6x
\n" ); document.write( "x = \"120%2F6\"
\n" ); document.write( "x = 20 mph is the go speed
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\n" ); document.write( "Check solution by finding the times
\n" ); document.write( "120/20 = 6 hrs
\n" ); document.write( "120/40 = 3 hrs
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\n" ); document.write( "differ = 3 hrs
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