document.write( "Question 141559: How do I solve?\r
\n" );
document.write( "\n" );
document.write( "A person traveled 120 miles in one direction. The return trip was accomplished at double the speed and took three hours less time. Find the speed going. \n" );
document.write( "
Algebra.Com's Answer #103145 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! How do I solve? \n" ); document.write( ": \n" ); document.write( "Let x = speed going \n" ); document.write( "then \n" ); document.write( "2x = return speed \n" ); document.write( ": \n" ); document.write( "A person traveled 120 miles in one direction. The return trip was accomplished at double the speed and took three hours less time. Find the speed going. \n" ); document.write( "; \n" ); document.write( "Write a time equation: Time = dist/speed \n" ); document.write( ": \n" ); document.write( "Going time = return time + 3 hrs \n" ); document.write( " \n" ); document.write( "Multiply equation by 2x to get rid of the denominator: \n" ); document.write( "2(120) = 120 + 3(2x) \n" ); document.write( ": \n" ); document.write( "240 = 120 + 6x \n" ); document.write( ": \n" ); document.write( "240 - 120 = 6x \n" ); document.write( ": \n" ); document.write( "120 = 6x \n" ); document.write( "x = \n" ); document.write( "x = 20 mph is the go speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the times \n" ); document.write( "120/20 = 6 hrs \n" ); document.write( "120/40 = 3 hrs \n" ); document.write( "--------------- \n" ); document.write( "differ = 3 hrs \n" ); document.write( " |