document.write( "Question 141561: How do I solve?\r
\n" ); document.write( "\n" ); document.write( "The additive inverse of a number divided by 12 is the same as one less than 3 times its reciprocal. Find the number. \n" ); document.write( "
Algebra.Com's Answer #103144 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Let x = \"a number\"
\n" ); document.write( "Additive inverse of a number = -x
\n" ); document.write( ":
\n" ); document.write( "Just write what it says:
\n" ); document.write( "\"The additive inverse of a number divided by 12 is the same as one less than 3 times its reciprocal.\"
\n" ); document.write( "\"%28-x%29%2F12\" = \"3%2Fx\" - 1
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by 12x and you have:
\n" ); document.write( "x(-x) = 12(3) - 12x(1)
\n" ); document.write( ":
\n" ); document.write( "-x^2 = 36 - 12x
\n" ); document.write( "arrange as a quadratic equation on the right
\n" ); document.write( "0 = +x^2 - 12x + 36
\n" ); document.write( "This easily factors to:
\n" ); document.write( "(x-6)(x-6) = 0
\n" ); document.write( "x = +6 is the number
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution in the statement;
\n" ); document.write( "\"The additive inverse of a number divided by 12 is the same as one less than 3 times its reciprocal.\"
\n" ); document.write( " \"%28%28-6%29%2F12%29\" = \"3%2F6\" - 1\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );