document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141510>Question 141510</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three faces of a box have a common vertex and their combined area is 20cm squared.  What is the total surface area of the box?\r<BR>\n" );
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document.write( "thank you.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103135 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Presuming it is a rectangular box, then three faces with a common vertex must have half the surface area of the entire box.  That's because a rectangular box could have 2 each of three differently dimensioned rectangles, but in order for three of the sides to have a common vertex, you would have to have one of each of the differently dimensioned rectangles, and the missing pieces would be exactly the same as to size and shape.  </SPAN>\n" );
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