document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21420>Question 21420</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sara can lap the swimming pool in 2.5 min. If she keeps the same pace,how many laps in 13 min.? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10313 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a rate problem. The key is: (rate * time) = distance.<BR>\n" );
document.write( "The rate for Sara is ( 1 lap / 2.5 min )<BR>\n" );
document.write( "She is keeping up this rate for 13 minutes.<BR>\n" );
document.write( "( 1 lap / 2.5 min ) * 13 min = L lap\r<BR>\n" );
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document.write( "Solve this for L.\r<BR>\n" );
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document.write( "Think of it this way.<BR>\n" );
document.write( "If she can lap the pool in 2.5 minutes, how much of the pool can she swim in just one minute? If she lapped the pool in 2 minutes, then in 1 minute, she'd <BR>\n" );
document.write( "swim 1/2 the length of the pool. 1/2.5 will give you the amount she can<BR>\n" );
document.write( "swim in just 1 minute.<BR>\n" );
document.write( "The answer is .4, so that is the fraction of the pool she can swim in 1 minute.<BR>\n" );
document.write( "In 13 minutes, she swims 13 times that or 13 X .4 = 5.2 laps. Hope this helps  </SPAN>\n" );
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