document.write( "Question 141445: A lawn mower of width 1m is used to mow a rectangular lawn of dimension 60mx40m. The mowing is done starting from the corner towards the center. How many times should the mower be moved along the garden for 3/4th of garden to be mowed? \n" ); document.write( "
Algebra.Com's Answer #103123 by ankor@dixie-net.com(22740)\"\" \"About 
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A lawn mower of width 1m is used to mow a rectangular lawn of dimension 60mx40m. The mowing is done starting from the corner towards the center. How many times should the mower be moved along the garden for 3/4th of garden to be mowed?
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\n" ); document.write( "Assume you mean 3/4 of the lawn, not the garden. (Big trouble if you mowed the garden around here.)
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\n" ); document.write( "Find the area of 3/4 of the lawn
\n" ); document.write( "60 * 40 * 3/4 = 1800 sq/m
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\n" ); document.write( "Let x = no. of rounds made on the lawn to complete 3/4 of it
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\n" ); document.write( "Each round subtracts two meters from both dimensions, so we have:
\n" ); document.write( "(60-2x)*(40-2x) = 1800
\n" ); document.write( "FOIL
\n" ); document.write( "2400 - 120x - 80x + 4x^2 = 1800
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\n" ); document.write( "2400 - 200x + 4x^2 - 1800 = 0
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "4x^2 - 200x + 600 = 0
\n" ); document.write( "simplify, divide by 4
\n" ); document.write( "x^2 - 50x + 150 = 0
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\n" ); document.write( "Use the quadratic formula to find x: a=1; b=-50; c=150
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\n" ); document.write( "The reasonable answer I got was approx 3.2 rounds \n" ); document.write( "
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