document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141500>Question 141500</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130443980/algebrahomeworkh>Prentice hall algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I am so stuck!  How do I solve using two equations with two variables?\r<BR>\n" );
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document.write( "The tens digit of a two-digit number is twice the units digit.  If the digits are reversed, the new number is 36 less than the original number.  Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #103097 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=103097\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the tens digit.<BR>\n" );
document.write( "Let y be the ones digit.\r<BR>\n" );
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document.write( "The number is then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10x+%2B+y ALIGN=MIDDLE  ALT=\"10x+%2B+y\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "(if x were 6 and y were 3, then the number would be 63 which is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%286%29%2B3 ALIGN=MIDDLE  ALT=\"10%286%29%2B3\"   DISABLED_style= \"max-width:90%; height:auto;\" >)\r<BR>\n" );
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document.write( "and we know that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+2y ALIGN=MIDDLE  ALT=\"x+=+2y\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The new number with the digits reversed must be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10y%2Bx ALIGN=MIDDLE  ALT=\"10y%2Bx\"   DISABLED_style= \"max-width:90%; height:auto;\" > and this is 36 less than the original number, so:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10x%2By-36=10y%2Bx ALIGN=MIDDLE  ALT=\"10x%2By-36=10y%2Bx\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  To solve, substitute <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y ALIGN=MIDDLE  ALT=\"2y\"   DISABLED_style= \"max-width:90%; height:auto;\" > for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" > because <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=2y ALIGN=MIDDLE  ALT=\"x=2y\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and then solve for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y ALIGN=MIDDLE  ALT=\"y\"   DISABLED_style= \"max-width:90%; height:auto;\" >, multiply by 2 to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and then construct the number.\r<BR>\n" );
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document.write( "Remember to check your work by constructing the number, reversing the digits, and then subtracting to make sure you get 36. </SPAN>\n" );
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