document.write( "Question 141479: A plane flies 300 miles with a tail wind in 1 hour. It takes the same plane 2 hours to fly
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document.write( "the 300 miles when flying against the wind. What is the plane’s speed in still air? \n" );
document.write( "
Algebra.Com's Answer #103078 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A plane flies 300 miles with a tail wind in 1 hour. It takes the same plane 2 hours to fly the 300 miles when flying against the wind. What is the plane’s speed in still air? \n" ); document.write( "--------- \n" ); document.write( "Let plane speed in still air be \"p\". \n" ); document.write( "Let wind speed be \"w\". \n" ); document.write( "------------------------ \n" ); document.write( "With wind DATA: \n" ); document.write( "distance = 300 ; time = 1 hr ; rate = 300/1 mph \n" ); document.write( "--------------------------- \n" ); document.write( "against wind DATA: \n" ); document.write( "distance = 300 ;time = 2 hr ; rate = 300/2 = 150 mph \n" ); document.write( "------------------------- \n" ); document.write( "EQUATIONS: \n" ); document.write( "p+w = 300 \n" ); document.write( "p-w = 150 \n" ); document.write( "--------------- \n" ); document.write( "Add to get: \n" ); document.write( "2p = 450 \n" ); document.write( "p = 225 mph (speed of plane in still air) \n" ); document.write( "---------------------------------- \n" ); document.write( "Substitute into p+w = 300 to solve for w: \n" ); document.write( "225 + w = 300 \n" ); document.write( "w = 75 mph (speed of the wind) \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |