document.write( "Question 141369This question is from textbook Prentice hall algebra 1
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document.write( ": i need solution.
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document.write( "In a two digit number the digit at ten place is twice the digit at unit place.on interchanging the digits the number is reduced by 18. find the number. \n" );
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Algebra.Com's Answer #103065 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=the 10's digit of the original number \n" ); document.write( "And let y= the unit's digit of the original number \n" ); document.write( "The original number is 10x+y; if the digits are reversed, the new number would be 10y+x\r \n" ); document.write( "\n" ); document.write( "Now we are told that:\r \n" ); document.write( "\n" ); document.write( "x=2y------------------------------eq1 \n" ); document.write( "and \n" ); document.write( "10x+y=10y+x+36-----------------------eq2\r \n" ); document.write( "\n" ); document.write( "substitute x=2y from eq1 into eq2 \n" ); document.write( "10*2y+y=10y+2y+36 simplify\r \n" ); document.write( "\n" ); document.write( "21y=12y+36 subtract 12y from each side\r \n" ); document.write( "\n" ); document.write( "21y-12y=12y-12y+36 collect like terms\r \n" ); document.write( "\n" ); document.write( "9y=36 divide each side by 9\r \n" ); document.write( "\n" ); document.write( "y=4---------------------------the unit's digit\r \n" ); document.write( "\n" ); document.write( "substitute y=4 into eq1 \n" ); document.write( "x=2*4=8--------------------------the 10's digit\r \n" ); document.write( "\n" ); document.write( "So, the number is 84\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "8=2*4 \n" ); document.write( "8=8 \n" ); document.write( "and \n" ); document.write( "48+36=84 \n" ); document.write( "84=84\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |