document.write( "Question 141385This question is from textbook Elementary and Intermediate Algebra
\n" ); document.write( ": this problem is on page 407. \r
\n" ); document.write( "\n" ); document.write( "1/2 +1/4x
\n" ); document.write( "--------- = I didn't get the same answer as the back of the book. It's
\n" ); document.write( "x/3 - 1/12x supposed to be 3/2x-1. I don't understand how they got that. Anne
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Algebra.Com's Answer #103022 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Hi Anne. Let's first look at the numerator:\r
\n" ); document.write( "\n" ); document.write( "(1/2)+(1/4x) We'll multiply each term by (4x/4x) and we get\r
\n" ); document.write( "\n" ); document.write( "(2x+1)/4x\r
\n" ); document.write( "\n" ); document.write( "Now lets look at the denominator:\r
\n" ); document.write( "\n" ); document.write( "(x/3)-(1/12x) We'll multiply each term by (12x/12x) and we get\r
\n" ); document.write( "\n" ); document.write( "(4x^2-1)/12x but 4x^2-1=(2x+1)(2x-1) so now we have\r
\n" ); document.write( "\n" ); document.write( "((2x+1)(2x-1))/12x\r
\n" ); document.write( "\n" ); document.write( "now let's put the numerator and denominator back together again:\r
\n" ); document.write( "\n" ); document.write( "\"%28%282x%2B1%29%2F4x%29%2F%28%282x%2B1%29%282x-1%29%2F12x%29\"\r
\n" ); document.write( "\n" ); document.write( "Now we'll multiply both the numerator and denominator by 12x/((2x-1)(2x+1))\r
\n" ); document.write( "\n" ); document.write( "and we get:\r
\n" ); document.write( "\n" ); document.write( "((2x+1)/4x)*12x/((2x-1)(2x+1))/1 and this gives us\r
\n" ); document.write( "\n" ); document.write( "3/(2x-1)\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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