document.write( "Question 141367This question is from textbook Prentice hall algebra 1
\n" ); document.write( ": How do I solve by using two equations in two variables?\r
\n" ); document.write( "\n" ); document.write( "Larry is 8 years older than his sister. In 3 years, he will be twice as old as she is now. How old are they now?
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Algebra.Com's Answer #103018 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Let x=sister's age
\n" ); document.write( "And let y=Larry's age
\n" ); document.write( "y+3=Larry's age 3 years from now\r
\n" ); document.write( "\n" ); document.write( "Now we are told the following:\r
\n" ); document.write( "\n" ); document.write( "y=x+8------------------------------------eq1
\n" ); document.write( "and
\n" ); document.write( "y+3=2x-----------------------------------eq2\r
\n" ); document.write( "\n" ); document.write( "substitute y=x+3 from eq1 into eq2\r
\n" ); document.write( "\n" ); document.write( "x+8+3=2x subtract x from each side\r
\n" ); document.write( "\n" ); document.write( "x-x+8+3=2x-x collect like terms\r
\n" ); document.write( "\n" ); document.write( "11=x or
\n" ); document.write( "x=11-------------------------------sister's age now
\n" ); document.write( "substitute into eq1\r
\n" ); document.write( "\n" ); document.write( "y=11+8=19----------------------------Larry's age now\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "19 is 8 years older than 11
\n" ); document.write( "and
\n" ); document.write( "22=2*11
\n" ); document.write( "22=22\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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