document.write( "Question 141361This question is from textbook Prentice hall algebra 1
\n" ); document.write( ": How do I solve using a system of two equations in two variables?\r
\n" ); document.write( "\n" ); document.write( "The sum of the digits of a two-digit number is 9. The value of the number is 12 times the tens digit. Find the number.\r
\n" ); document.write( "\n" ); document.write( "I think the first equation is x+y=9
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Algebra.Com's Answer #103012 by checkley77(12844)\"\" \"About 
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X+Y=9
\n" ); document.write( "X=9-Y
\n" ); document.write( "10X+Y=12X
\n" ); document.write( "10(9-Y)+Y=12(9-Y)
\n" ); document.write( "90-10Y+Y=108-12Y
\n" ); document.write( "-10Y+1Y+12Y=108-90
\n" ); document.write( "3Y=18
\n" ); document.write( "Y=18/3
\n" ); document.write( "Y=6 ANSWER FOR THE UNITS DIGIT.
\n" ); document.write( "X=9-6
\n" ); document.write( "X=3
\n" ); document.write( "PROOF
\n" ); document.write( "36=12*3
\n" ); document.write( "36=36
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