document.write( "Question 141360This question is from textbook Prentice hall algebra 1
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document.write( "How do I solve by using a system of two equations in two variables?
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document.write( "Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5 years ago. Find their ages now. \n" );
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Algebra.Com's Answer #103003 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! set up the following equation: \n" ); document.write( "J=S+6 THIS SAYS JENNIFER IS 6 YEARS OLDER THAN SUE. \n" ); document.write( "J+4=2(S+6-5) THIS EQUATION SAYS THAT IN 4 YEARS (J+4)JENNIFER = (WILL BE) 2 TIMES AS OLD AS SUE WAS 5 YEARS AGO 2(S+6-5). \n" ); document.write( "NOW SOLVE FOR S BY SUBSTITUTING (S+6) FOR J IN THE SECOND EQUATION. \n" ); document.write( "(S+6)+4=2(S+6-5) \n" ); document.write( "S+6+4=2(S+1) \n" ); document.write( "S+10=2S+2 \n" ); document.write( "S-2S=2-10 \n" ); document.write( "-S=-8 \n" ); document.write( "S=8 SUE'S AGE NOW. \n" ); document.write( "J=8+6=14 JENNIFER'S AGE NOW. \n" ); document.write( "PROOF: \n" ); document.write( "14+4=2(8+6-5) \n" ); document.write( "18=2(9) \n" ); document.write( "18=18 \n" ); document.write( " |