document.write( "Question 141360This question is from textbook Prentice hall algebra 1
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\n" ); document.write( "How do I solve by using a system of two equations in two variables?
\n" ); document.write( "Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5 years ago. Find their ages now.
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Algebra.Com's Answer #103003 by checkley77(12844)\"\" \"About 
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set up the following equation:
\n" ); document.write( "J=S+6 THIS SAYS JENNIFER IS 6 YEARS OLDER THAN SUE.
\n" ); document.write( "J+4=2(S+6-5) THIS EQUATION SAYS THAT IN 4 YEARS (J+4)JENNIFER = (WILL BE) 2 TIMES AS OLD AS SUE WAS 5 YEARS AGO 2(S+6-5).
\n" ); document.write( "NOW SOLVE FOR S BY SUBSTITUTING (S+6) FOR J IN THE SECOND EQUATION.
\n" ); document.write( "(S+6)+4=2(S+6-5)
\n" ); document.write( "S+6+4=2(S+1)
\n" ); document.write( "S+10=2S+2
\n" ); document.write( "S-2S=2-10
\n" ); document.write( "-S=-8
\n" ); document.write( "S=8 SUE'S AGE NOW.
\n" ); document.write( "J=8+6=14 JENNIFER'S AGE NOW.
\n" ); document.write( "PROOF:
\n" ); document.write( "14+4=2(8+6-5)
\n" ); document.write( "18=2(9)
\n" ); document.write( "18=18
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