document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141336>Question 141336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 2.4 units long. The longer leg is 1.7 units longer than the shorter leg. Find the lengths of the sides of the triangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102985 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102985\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> hyp=2.4\r<BR>\n" );
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document.write( "let l=longer leg, s= shorter leg\r<BR>\n" );
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document.write( "l=1.7+s\r<BR>\n" );
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document.write( "From the Pythagorean Theorem, a^2+b^2=c^2, c=hypotenuse.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2%2B%281.7%2Bs%29%5E2=2.4%5E2 ALIGN=MIDDLE  ALT=\"s%5E2%2B%281.7%2Bs%29%5E2=2.4%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2%2B1.7%5E2%2B3.4s%2Bs%5E2=2.4%5E2 ALIGN=MIDDLE  ALT=\"s%5E2%2B1.7%5E2%2B3.4s%2Bs%5E2=2.4%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2s%5E2%2B3.4s%2B2.89=5.76 ALIGN=MIDDLE  ALT=\"2s%5E2%2B3.4s%2B2.89=5.76\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2s%5E2%2B3.4s-2.87=0 ALIGN=MIDDLE  ALT=\"2s%5E2%2B3.4s-2.87=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Normally we would continue here by applying the quadratic formula, however I see a factorization to make it easier:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28-.618843%2Bs%29%280.231884%2Bs%29=0 ALIGN=MIDDLE  ALT=\"2%28-.618843%2Bs%29%280.231884%2Bs%29=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The only answer that makes sense (that is, it is positive), is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s=.618843 ALIGN=MIDDLE  ALT=\"s=.618843\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "So, l=1.7+s=1.7+.618843=2.31884.<BR>\n" );
document.write( "Now, check:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.618843%5E2%2B%28.618843%2B1.7%29%5E2=.382967%2B5.37703=5.76 ALIGN=MIDDLE  ALT=\".618843%5E2%2B%28.618843%2B1.7%29%5E2=.382967%2B5.37703=5.76\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.4%5E2=5.76 ALIGN=MIDDLE  ALT=\"2.4%5E2=5.76\"   DISABLED_style= \"max-width:90%; height:auto;\" >. This completes the problem.<BR>\n" );
document.write( " </SPAN>\n" );
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