document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141284>Question 141284</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 cm more than 2 times its width.  If the area of the rectangle os 93cm squared, what is the length and the width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102972 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W+3<BR>\n" );
document.write( "W(2W+3)=93<BR>\n" );
document.write( "2W^2+3W-93=0<BR>\n" );
document.write( "USING THE QUADRATIC EQUATION:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%28-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29 ALIGN=MIDDLE  ALT=\"x=%28-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > WE GET:<BR>\n" );
document.write( "W=(-3+-SQRT[3^2-4*2*-93])/2*2<BR>\n" );
document.write( "W=(-3+-SQT[9+744])/4<BR>\n" );
document.write( "W=(-3+-[SQRT753])/4<BR>\n" );
document.write( "W=(-3+-27.44)/4<BR>\n" );
document.write( "W=(-3+27.44)/4<BR>\n" );
document.write( "W=24.44/4<BR>\n" );
document.write( "W=6.11 ANSWER FOR THE WIDTH.<BR>\n" );
document.write( "L=2*6.11+3=12.22+3=15.22 ANSWER FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "6.11*15.22=93<BR>\n" );
document.write( "92.99~93  </SPAN>\n" );
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