document.write( "Question 141324: Please help me solve this equation:\r
\n" ); document.write( "\n" ); document.write( " $\"log%287%2C%28x%2B4%29%29+%2B+log%287%2C%28x-2%29%29+=+1\"$ , $\"x%3E2\"$ \n" ); document.write( "

Algebra.Com's Answer #102971 by Edwin McCravy(20059) $\"\"$ $\"About$

You can put this solution on YOUR website!
Please help me solve this equation:\r
\n" ); document.write( "\n" ); document.write( " $\"log%287%2C%28x%2B4%29%29+%2B+log%287%2C%28x-2%29%29+=+1\"$ , $\"x%3E2\"$
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document.write( "Use this rule on the left side:\r\n" );
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document.write( "Now use this rule to rewrite the equation:\r\n" );
document.write( "                is equivalent to \r\n" );
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document.write( "Simplify, FOIL out the right side:\r\n" );
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document.write( ",  \r\n" );
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document.write( "Get  on the left by subtracting\r\n" );
document.write( "7 from both sides:\r\n" );
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document.write( "Factor the right side:\r\n" );
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document.write( "             \r\n" );
document.write( "Use the zero-factor principle:\r\n" );
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document.write( "x-3=0 gives x=3\r\n" );
document.write( "x+5=0 gives x=-5\r\n" );
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document.write( "However we must discard that second answer\r\n" );
document.write( "because we are given the restriction that \r\n" );
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document.write( "So the only solution is \r\n" );
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document.write( "Edwin

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