document.write( "Question 141325This question is from textbook McDougal Litell Algebra 2
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\n" ); document.write( "I remember going over cubes and I can solve the problems with \"x%5E2\" but the cubes confuse me.
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Algebra.Com's Answer #102966 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Then until you get used to cubes and higher exponents\r\n" );
document.write( "just get rid of all exponents first and write \"x%5E3\"\r\n" );
document.write( "as \"x%2Ax%2Ax\" and \"y%5E2\" as \"y%2Ay\", etc.\r\n" );
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document.write( "Also break \"15\" into a product of primes\r\n" );
document.write( "and write it as as \"3%2A5\"\r\n" );
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document.write( "So,\r\n" );
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document.write( "\"%285x%5E3y%29%2F%28x%5E2y%5E2%29\".\"y%5E3%2F%2815x%5E2%29\"\r\n" );
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document.write( "becomes\r\n" );
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document.write( "\"%285%2Ax%2Ax%2Ax%2Ay%29%2F%28x%2Ax%2Ay%2Ay%29\".\"y%2Ay%2Ay%2F%283%2A5%2Ax%2Ax%29\" \r\n" );
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document.write( "Indicate the multiplication of the numerators and\r\n" );
document.write( "the denominators so that you only have one\r\n" );
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document.write( "\"%285%2Ax%2Ax%2Ax%2Ay%2Ay%2Ay%2Ay%29%2F%283%2A5%2Ax%2Ax%2Ax%2Ax%2Ay%2Ay%29\"\r\n" );
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document.write( "Now cancel:\r\n" );
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document.write( "So all that's left is\r\n" );
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document.write( "\"%28y%2Ay%29%2F%283x%29\"\r\n" );
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document.write( "and we write \"y%2Ay\" as \"y%5E2\" and end up with\r\n" );
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document.write( "\"y%5E2%2F%283x%29\"\r\n" );
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document.write( "This method will always work, and you can use it\r\n" );
document.write( "until you can see that it's quicker just to subtract\r\n" );
document.write( "the exponents, which would amount to subtracting\r\n" );
document.write( "the number of \"x\"'s or \"y\"'s which would \r\n" );
document.write( "cancel in the mathod shown above.\r\n" );
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document.write( "Edwin
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