document.write( "Question 141257: I'm trying to help my daughter with her science fair project. Her project was to find out if 3 different shaped containers(we used cylinder, round and square)with the same volume of water (355ml) in each, then frozen, would melt at the same or different speeds. I know that the one with the larger surface area will melt faster but what I'm not sure of is how to find out the surface area of each container. I didn't think it would be accurate to use the traditional surface area formula, measuring the container since the container isn't filled all the way. Hope this makes sense. \n" ); document.write( "
Algebra.Com's Answer #102950 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
You MUST fill the containers completely.
\n" ); document.write( "They must be frozen in the same space so they are at the same temp.
\n" ); document.write( ".
\n" ); document.write( "Sphere:
\n" ); document.write( "V=(4pi*r^3)/3
\n" ); document.write( "355=(4pi*r^3)/3
\n" ); document.write( "355*3=4pi*r^3
\n" ); document.write( "1065/4=pi*r^3
\n" ); document.write( "266.25=pi*r^3
\n" ); document.write( "r^3=266.25/pi
\n" ); document.write( "r^3=84.75...
\n" ); document.write( "r=4.39... cm
\n" ); document.write( "d=8.8... cm. (diameter of the sphere)
\n" ); document.write( ".
\n" ); document.write( "Cube:
\n" ); document.write( "s^3=V
\n" ); document.write( "s^3=355
\n" ); document.write( "s=7.0... cm (length of a side of the cube)
\n" ); document.write( ".
\n" ); document.write( "Cylinder:
\n" ); document.write( "pi*r^2*h=V
\n" ); document.write( "Let the height be 10 cm
\n" ); document.write( "pi*r^2*10=355
\n" ); document.write( "pi*r^2=355/10=35.5
\n" ); document.write( "r^2=35.5/pi=11.3...
\n" ); document.write( "r=3.36
\n" ); document.write( "d=6.7...cm.
\n" ); document.write( ".
\n" ); document.write( "With the above measurements you can construct your containers.
\n" ); document.write( "You might make them out of clay.
\n" ); document.write( ".
\n" ); document.write( "Surface Areas:
\n" ); document.write( "Sphere:
\n" ); document.write( "4pi*r^2
\n" ); document.write( "4pi*4.39^2=242 cm^2
\n" ); document.write( ".
\n" ); document.write( "Cube:
\n" ); document.write( "49*6=294 cm^2
\n" ); document.write( ".
\n" ); document.write( "Cylinder:
\n" ); document.write( "2pi*r*h+2pi*r^2
\n" ); document.write( "=2pi*3.36*10 + 2pi*3.36^2
\n" ); document.write( "=211+71
\n" ); document.write( "=282 cm^2
\n" ); document.write( ".
\n" ); document.write( "The sphere should melt last.
\n" ); document.write( ".
\n" ); document.write( "Good luck with your adventure!
\n" ); document.write( ".
\n" ); document.write( "Ed\r
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