document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141293>Question 141293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle has a perimeter of 38 cm. three-fourths  of its width is equal to one-fifth of its length. what is the measure of the length? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102947 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102947\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A) 2L+2w=38<BR>\n" );
document.write( "B) <BR>\n" );
document.write( "L/5 = 3w/4<BR>\n" );
document.write( "4L=15w Multiply each side by 20 to eliminate fractions.<BR>\n" );
document.write( "4L-15w=0<BR>\n" );
document.write( ".<BR>\n" );
document.write( "-4L-4w=-76 multiply A) by -2<BR>\n" );
document.write( "4L-15w=0<BR>\n" );
document.write( "-----------add<BR>\n" );
document.write( "==>-19w=-76<BR>\n" );
document.write( "w=4 cm<BR>\n" );
document.write( "L=15*4/4<BR>\n" );
document.write( "=15 cm<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "A) 2*15 + 2*4 = 38 true<BR>\n" );
document.write( "B) 15/5=3*4/4 true<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );