document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141264>Question 141264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a recipe calls for 3/4 of a pound of sausage. How much sausage should be used if only 1/3 of the recipe is being made. Write the answer in simplest form. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102923 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/3*3/4=3/12=1/4 of a pound is needed. </SPAN>\n" );
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