document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21008>Question 21008</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help! We're working with sequencing; I'm supposed to figure out which number comes next. I have no clue: \r<BR>\n" );
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document.write( "4, 6, 9, 13.5,?\r<BR>\n" );
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document.write( "12, -4, 4/3, -4/9, ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10291 by </B><A HREF=/tutors/aboutme.mpl?userid=Photonjohn><B>Photonjohn(42)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Photonjohn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the first series, divide the first number by 2 and add it to that number, and so on.  4 +4/2 = 6.   6 + 6/2 = 9.  9 + 9/2 = 13.5   13.5 + 13.5/2 = ?\r<BR>\n" );
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document.write( "for the next series,<BR>\n" );
document.write( "divide each number by -3 as the next number.<BR>\n" );
document.write( "12/(-3) = -4<BR>\n" );
document.write( "-4/(-3) = 4/3<BR>\n" );
document.write( "(4/3)/(-3) = -4/9<BR>\n" );
document.write( "etc. </SPAN>\n" );
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