document.write( "Question 141236: Well i have to solve the following system of equations by substitution\r
\n" ); document.write( "\n" ); document.write( "0.5x-2y=1
\n" ); document.write( "-3y+x=4\r
\n" ); document.write( "\n" ); document.write( "I understand that I must get of the the equations to equal to either x or y so i can substitute.\r
\n" ); document.write( "\n" ); document.write( "i'll try the second one\r
\n" ); document.write( "\n" ); document.write( "-3y+x=4\r
\n" ); document.write( "\n" ); document.write( "x=4-3y is that right? if so, what to do next?
\n" ); document.write( "

Algebra.Com's Answer #102892 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
0.5x-2y=1
\n" ); document.write( "-3y+x=4
\n" ); document.write( "I understand that I must get of the the equations to equal to either x or y so i can substitute.
\n" ); document.write( "i'll try the second one
\n" ); document.write( "-3y+x=4
\n" ); document.write( "x=4-3y is that
\n" ); document.write( "---------------
\n" ); document.write( "Substitute that into 5x-2y=1 to solve for \"y\":
\n" ); document.write( "0.5(4-3y)- 2y = 1
\n" ); document.write( "2 - (3/2)y - 2y = 1
\n" ); document.write( "-7/2 y = -1
\n" ); document.write( "y = 2/7
\n" ); document.write( "--------------------
\n" ); document.write( "Substitute into x = 4-3y
\n" ); document.write( "x = 4-3(2/7)
\n" ); document.write( "x = 4-6/7
\n" ); document.write( "x = 22/7
\n" ); document.write( "-----------------------------
\n" ); document.write( "Checking:
\n" ); document.write( "0.5x-2y = 1
\n" ); document.write( "0.5(22/7) -2(2/7) = 1
\n" ); document.write( "11/7 - 4/7 = 1
\n" ); document.write( "7/7 = 1
\n" ); document.write( "1 = 1
\n" ); document.write( "===========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );