document.write( "Question 141145: Solve \r
\n" ); document.write( "\n" ); document.write( "(2x + 3y = 7
\n" ); document.write( "(x - 2y = 7 (Use substitution.)
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Algebra.Com's Answer #102869 by nabla(475)\"\" \"About 
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From the second equation,
\n" ); document.write( "(1) x=7+2y
\n" ); document.write( "plug (1) into the first equation:
\n" ); document.write( "2(7+2y)+3y=7
\n" ); document.write( "14+4y+3y=7
\n" ); document.write( "7y+14=7
\n" ); document.write( "(2) y=-1\r
\n" ); document.write( "\n" ); document.write( "Now, plug (2) into (1):
\n" ); document.write( "x=7+2(-1)
\n" ); document.write( "(3) x=5\r
\n" ); document.write( "\n" ); document.write( "Now, check to make sure these are correct:\r
\n" ); document.write( "\n" ); document.write( "2(5) + 3(-1) =10-3=7
\n" ); document.write( "5 - 2(-1) = 7
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