document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141202>Question 141202</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many real zeroes are there in f(x) = x^3 + 27\r<BR>\n" );
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document.write( "a.  3<BR>\n" );
document.write( "b.  1<BR>\n" );
document.write( "c.  None, you cannot factor this polynomial<BR>\n" );
document.write( "d.  None of the above\r<BR>\n" );
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document.write( "I figured b. 1 because the factors of 27 are 1, 3, 9, 27 and the factors of 1 is 1.  So they only have one factor in common. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102864 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102864\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, note that the statement is the same as:\r<BR>\n" );
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document.write( "f(x)=x^3+3^3=(x+3)(x^2-3x+9) by the formula for the sum of cubes.\r<BR>\n" );
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document.write( "Attempting to find the zeros, we set f(x)=0:<BR>\n" );
document.write( "(x+3)(x^2-3x+9)=0\r<BR>\n" );
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document.write( "This can only be when<BR>\n" );
document.write( "x=-3  or x^2-3x+9=0<BR>\n" );
document.write( "We can see that the second will not have any real roots because the discriminant is negative b^2-4ac=9-4(1)(9)=-27. <BR>\n" );
document.write( "Thus, your choice of b is correct, but I would recommend using the method I have done here to determine the amount of roots of a polynomial. </SPAN>\n" );
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