document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141204>Question 141204</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When factoring the following by the reverse FOIL method, the factors of 6 must add up to what value?\r<BR>\n" );
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document.write( "I have no clue as to where to begin.\r<BR>\n" );
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document.write( "f(x) = x^2 + 5x + 6\r<BR>\n" );
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document.write( "a. 1<BR>\n" );
document.write( "b.  1+6+5=12<BR>\n" );
document.write( "c.  6<BR>\n" );
document.write( "d. 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102859 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Consider the following:\r<BR>\n" );
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document.write( "(1)f(x)=(x+1)(x+2)<BR>\n" );
document.write( "expand it:<BR>\n" );
document.write( "(2)f(x)=x^2+2x+1x+2<BR>\n" );
document.write( "(3)f(x)=x^2+3x+2\r<BR>\n" );
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document.write( "Similar to the problem you proposed, we could ask \"the factors of 2 must add up to what value?\" What are the factors of 2? They add up to what? From (2) above, we see that 2 and 1 are the coefficients of individual x terms from the expansion. Thus, to address your problem we need to find out the factors of 6 that add up to 5. It is the same process.\r<BR>\n" );
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document.write( "Your problem factors as f(x)=(x+3)(x+2). It should be evident by now that the correct answer is d.5.<BR>\n" );
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