document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21377>Question 21377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> SIMPLIFY -2Y3  X-2(X TO THE NEGATIVE 2 POWER)  AND Y TOTEH 3RD POWER<BR>\n" );
document.write( "SO FAR I HAVE  X-2Y3=X(-2)Y(3)=    I DONT KNOW HOW TO FINISH IT </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10285 by </B><A HREF=/tutors/aboutme.mpl?userid=Photonjohn><B>Photonjohn(42)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Photonjohn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think you will have -2Y^3/X^2 if I interpret your question correctly.<BR>\n" );
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