document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=141112>Question 141112</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I, seem to be having some confuse here I need to calculate the of the discriminant of part(a) x^2+4x+4. Then by examining the sign of the discriminant in part(a) how many x-intercepts would the graph of y=x^2+4x+4 have? and Why? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102796 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ax^2+bx+c=0 is a quadratic equation<BR>\n" );
document.write( "The discriminant is b^2-4ac. If it is negative then its square root will not be real and its 2 roots will be imaginary. If it is positive there are 2 real roots. If it is zero then there is one real root.<BR>\n" );
document.write( "a=1, b=4, c=4<BR>\n" );
document.write( "For the case at hand, 16-4*4=0 There is one real root.<BR>\n" );
document.write( "x^2+4x+4=0<BR>\n" );
document.write( "(x+2)^2=0<BR>\n" );
document.write( "x=-2<BR>\n" );
document.write( "-2 is the only root.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( ".<BR>\n" );
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