document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21380>Question 21380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hello,\r<BR>\n" );
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document.write( "  First let me tell you i'm sorry to ask for so much help so soon, but i have my math final on monday forgot after 15 weeks how to answer these 5-6 problems. Can somebody be a pal and help me find the soulutions to these problems before monday? 3 of them are solving the equation, 1 is seeing if a given number is a solution and the last two are word problems Please Help me!!!!\r<BR>\n" );
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document.write( "1.) solve these 3 equations\r<BR>\n" );
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document.write( "-3y (3y-3) - 2y = 8\r<BR>\n" );
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document.write( "2.) 6-5s /3 = s\r<BR>\n" );
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document.write( "3.) 5 (1 - x) / 6 = -x i got -5.166666666 is that right\r<BR>\n" );
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document.write( "4.) is see if the given number is a soulution?\r<BR>\n" );
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document.write( " 2, 2 / a+1 + 4 = 10 / a+1\r<BR>\n" );
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document.write( "5.) thise are word problems the first one is a drt problem and the second one is a $$ problem Please Help Me!!!\r<BR>\n" );
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document.write( " Two trains are 200 miles apart and their speeds differ by 10mph. find the the speed of each train if they are traveling toward each other and will meet in 2 hours. -------mph, ----- mph.\r<BR>\n" );
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document.write( "A collection of coins consisting of dimes and quarters has a value of $4.25. If the number of dimes is 2 more than twice the number of quarters , how many of each type of coins are there???\r<BR>\n" );
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document.write( " Once again i know this a lot to take on at once so i apologise for all these problems  But i'm really stuck on these and the help you provide wil help me on my final monday thanks for looking and helping me it means a lot. Have a Merry Christmas!!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10279 by </B><A HREF=/tutors/aboutme.mpl?userid=Photonjohn><B>Photonjohn(42)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Photonjohn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.  -3y(3y-3) - 2y = 8<BR>\n" );
document.write( "-9y^2 + 9y -2y = 8<BR>\n" );
document.write( "9y^2 - 7y +8 = 0  representing ax^2 + bx + c = 0,<BR>\n" );
document.write( "using the quadratic equation (-b +- (b^2 - 4ac)^1/2 )/2a<BR>\n" );
document.write( "y = (7+-(49-4(9)(8))^1/2 )/18<BR>\n" );
document.write( "y = (7+-(-239)^1/2 )/18<BR>\n" );
document.write( "y = (7+-i(239)^1/2 )/18<BR>\n" );
document.write( "y = 0.38888 +- 0.8589i<BR>\n" );
document.write( "are you sure you have the equation correct?\r<BR>\n" );
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document.write( "2. 6-5S/3 = S<BR>\n" );
document.write( "6 = S +5S/3<BR>\n" );
document.write( "6 = (8/3)S<BR>\n" );
document.write( "S = 9/4\r<BR>\n" );
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document.write( "3.  5(1-X)/6 = -X<BR>\n" );
document.write( "(5-5D)/6 = -X<BR>\n" );
document.write( "5-5X = -6X<BR>\n" );
document.write( "X = -5\r<BR>\n" );
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document.write( "4. 2 is the answer, then<BR>\n" );
document.write( "2/a + 1 + 4 = 10/a + 1<BR>\n" );
document.write( "2/2 + 1 + 4 = 10/2 + 1<BR>\n" );
document.write( "1 + 1 + 4 = 5 + 1<BR>\n" );
document.write( "6 = 6\r<BR>\n" );
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document.write( "5.  Let X = Speed of one train, X+10 = Speed of 2nd train.<BR>\n" );
document.write( "    Let t = time<BR>\n" );
document.write( "Then 200 miles = Xt + (X+10)t<BR>\n" );
document.write( "If they traveled for t=2 hours<BR>\n" );
document.write( "200 = 2X + 2(X+10)<BR>\n" );
document.write( "200 = 4X + 20<BR>\n" );
document.write( "4X = 180<BR>\n" );
document.write( "X = 45 mph for 1st Train<BR>\n" );
document.write( "and X+10 = 55 mph for 2nd Train\r<BR>\n" );
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document.write( "6.  Let D = # dimes, Q = # Quarters<BR>\n" );
document.write( "D = 2Q + 2<BR>\n" );
document.write( ".10D + .25Q = 4.25<BR>\n" );
document.write( "Subsitute D = 2Q + 2 into 2nd equation yields<BR>\n" );
document.write( ".2Q + .2 + .25Q = 4.25<BR>\n" );
document.write( ".45Q = 4.05<BR>\n" );
document.write( "Q = 9 quarters<BR>\n" );
document.write( "Then D = 2x9 + 2 = 20 Dimes\r<BR>\n" );
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document.write( "You'll ace the test now.<BR>\n" );
document.write( " </SPAN>\n" );
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