document.write( "Question 141103This question is from textbook
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document.write( ": I would really appreciate any feedback( help ) with what I need to do. The problem is a certain amount of money in invested at 8% per year, and 1500$ more than that amount is invested at 9% per year. The annual interest from the 9% investment exceeds the annual interest from the 8% investment by 160$. How much is invested at each rate? This is what I set up.
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document.write( ".08x+.09(x+1500) = 160+??????????? thank you in advance for your imput \n" );
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Algebra.Com's Answer #102783 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! you're doing fine __ the 160 is the difference, so just adjust your equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".09(x+1500)-.08x=160 __ multiply by 100 to clear decimals __ 9x+13500-8x=16000 __ x=2500 \n" ); document.write( " |