document.write( "Question 141093: Find 2 numbers such that their sum, their difference, and their product have the ratio 3:2:5. \n" ); document.write( "
Algebra.Com's Answer #102777 by ankor@dixie-net.com(22740)\"\" \"About 
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ratio 3:2:5.
\n" ); document.write( "ind 2 numbers such that their sum, their difference, and their product have the ratio 3:2:5.
\n" ); document.write( ":
\n" ); document.write( "Let the two numbers be x & y:
\n" ); document.write( "\"%28x%2By%29%2F%28x-y%29\" = \"3%2F2\"
\n" ); document.write( "Cross multiply:
\n" ); document.write( "2(x+y) = 3(x-y)
\n" ); document.write( "2x + 2y = 3x - 3y
\n" ); document.write( "3y + 2y = 3x - 2x
\n" ); document.write( "5y = x
\n" ); document.write( ":
\n" ); document.write( "and
\n" ); document.write( "\"%28x-y%29%2F%28xy%29\" = \"2%2F5\"
\n" ); document.write( "Cross multiply:
\n" ); document.write( "5(x-y) = 2xy
\n" ); document.write( "5x - 5y = 2xy
\n" ); document.write( "5x - 2xy = 5y
\n" ); document.write( "x(5-2y) = 5y
\n" ); document.write( "x = \"5y%2F%285-2y%29\"
\n" ); document.write( "Substitute 5y for x
\n" ); document.write( "5y = \"5y%2F%285-2y%29\"
\n" ); document.write( "Just looking at this we can assume
\n" ); document.write( "(5-2y) = 1
\n" ); document.write( "-2y = 1 - 5
\n" ); document.write( "-2y = -4
\n" ); document.write( "y = +2
\n" ); document.write( ":
\n" ); document.write( "Therefore:
\n" ); document.write( "x = 5(2)
\n" ); document.write( "x = 10
\n" ); document.write( ":
\n" ); document.write( "Testing the solution: x=10, y=2
\n" ); document.write( "\"12%2F8\" = \"3%2F2\"
\n" ); document.write( "and
\n" ); document.write( "\"8%2F20\" = \"2%2F5\" \n" ); document.write( "
\n" );