document.write( "Question 140983This question is from textbook Prentice Hall Algebra 1
\n" ); document.write( ": How do I solve this system of equations by using multiplication with the addition method?\r
\n" ); document.write( "\n" ); document.write( "1/5(x+2y)=-2
\n" ); document.write( "x/4-3y/2=15/2
\n" ); document.write( "

Algebra.Com's Answer #102687 by ankor@dixie-net.com(22740)\"\" \"About 
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How do I solve this system of equations by using multiplication with the addition method?
\n" ); document.write( ":
\n" ); document.write( "1/5(x+2y) = -2
\n" ); document.write( "Multiply by 5 to get rid of the denominator
\n" ); document.write( "x + 2y = 5(-2)
\n" ); document.write( "x + 2y = -10
\n" ); document.write( ":
\n" ); document.write( "\"x%2F4\" - \"%283y%29%2F2\" = \"15%2F2\"
\n" ); document.write( "Multiply equation by 4 to get rid of the denominator, resulting:
\n" ); document.write( "x - 2(3y) = 2(15)
\n" ); document.write( "x - 6y = 30
\n" ); document.write( ":
\n" ); document.write( "Multiply the 1st equation by -1 and add to the above equation
\n" ); document.write( "-x - 2y = +10
\n" ); document.write( "+x - 6y = +30
\n" ); document.write( "-----------------
\n" ); document.write( "0x - 8y = +40
\n" ); document.write( "y = \"40%2F%28-8%29\"
\n" ); document.write( "y = -5
\n" ); document.write( ":
\n" ); document.write( "Find x using x - 6y = 30:
\n" ); document.write( "x - 6(-5) = 30
\n" ); document.write( "x + 30 = 30
\n" ); document.write( "x = 0
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check solution using the 1st original equation:
\n" ); document.write( "1/5(x + 2y) = -2
\n" ); document.write( "1/5(0 + 2(-5) =
\n" ); document.write( "1/5 * -10 = -2
\n" ); document.write( "
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