document.write( "Question 140983This question is from textbook Prentice Hall Algebra 1
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document.write( ": How do I solve this system of equations by using multiplication with the addition method?\r
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document.write( "1/5(x+2y)=-2
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document.write( "x/4-3y/2=15/2 \n" );
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Algebra.Com's Answer #102687 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! How do I solve this system of equations by using multiplication with the addition method? \n" ); document.write( ": \n" ); document.write( "1/5(x+2y) = -2 \n" ); document.write( "Multiply by 5 to get rid of the denominator \n" ); document.write( "x + 2y = 5(-2) \n" ); document.write( "x + 2y = -10 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply equation by 4 to get rid of the denominator, resulting: \n" ); document.write( "x - 2(3y) = 2(15) \n" ); document.write( "x - 6y = 30 \n" ); document.write( ": \n" ); document.write( "Multiply the 1st equation by -1 and add to the above equation \n" ); document.write( "-x - 2y = +10 \n" ); document.write( "+x - 6y = +30 \n" ); document.write( "----------------- \n" ); document.write( "0x - 8y = +40 \n" ); document.write( "y = \n" ); document.write( "y = -5 \n" ); document.write( ": \n" ); document.write( "Find x using x - 6y = 30: \n" ); document.write( "x - 6(-5) = 30 \n" ); document.write( "x + 30 = 30 \n" ); document.write( "x = 0 \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution using the 1st original equation: \n" ); document.write( "1/5(x + 2y) = -2 \n" ); document.write( "1/5(0 + 2(-5) = \n" ); document.write( "1/5 * -10 = -2 \n" ); document.write( " |