document.write( "Question 141013: Evaluate\r
\n" ); document.write( "\n" ); document.write( "f(-2/3) if f(x) = x/2
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Algebra.Com's Answer #102657 by checkley77(12844)\"\" \"About 
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f(-2/3)
\n" ); document.write( "f(x) = x/2
\n" ); document.write( "f(-2/3)=(-2/3)/2
\n" ); document.write( "f(-2/3)=-2/3*1/2
\n" ); document.write( "f(-2/3)=-2/6
\n" ); document.write( "f(-2/3)=-1/3 answer.
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