document.write( "Question 140980This question is from textbook Prentice Hall Algebra 1
\n" ); document.write( ": How do I solve this system of equations using multiplication and addition method?\r
\n" ); document.write( "\n" ); document.write( "a/6 + b/4=5/2
\n" ); document.write( "2a/3 - b/2=-2\r
\n" ); document.write( "\n" ); document.write( "Hope you can understand this
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Algebra.Com's Answer #102641 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
Sure!
\n" ); document.write( "Let's simplify 1st this eqn:
\n" ); document.write( "a/6 + b/4=5/2
\n" ); document.write( "a=(5/2 - b/4)/6
\n" ); document.write( "a= 30/2 - 6b/4
\n" ); document.write( "a= 15 - 3b/2 ------ mark eqn 1. oks
\n" ); document.write( "Now, this value of \"a\" we substitute it to the other eqn but first let simplify it,
\n" ); document.write( "2a/3 - b/2=-2 ----- mark eqn 2 oks
\n" ); document.write( "becomes,
\n" ); document.write( "b/2=2a/3 +2 , and we subsitute \"a\" as shown in eqn 1 here.
\n" ); document.write( "So, b/2= 2(15 -3b/2)/3 +2
\n" ); document.write( "b/2 = [2(30 - 3b)/2]/3 +2
\n" ); document.write( "b/2 (30-3b)/3 +2
\n" ); document.write( "b/2= (30-3b+6)/3
\n" ); document.write( "3b=60-6b+12
\n" ); document.write( "3b+9b=72
\n" ); document.write( "b=8
\n" ); document.write( "For \"a\", go back eqn 1: a=15 - 3(8)/2=15-12
\n" ); document.write( "a=3
\n" ); document.write( "In doubt? Simply go back to your eqn 2 to check,
\n" ); document.write( "2(3)/3 - (8/2) =-2
\n" ); document.write( "2-4=-2
\n" ); document.write( "-2=-2, cool!
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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