document.write( "Question 140980This question is from textbook Prentice Hall Algebra 1
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document.write( ": How do I solve this system of equations using multiplication and addition method?\r
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document.write( "a/6 + b/4=5/2
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document.write( "2a/3 - b/2=-2\r
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document.write( "Hope you can understand this \n" );
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Algebra.Com's Answer #102641 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! Sure! \n" ); document.write( "Let's simplify 1st this eqn: \n" ); document.write( "a/6 + b/4=5/2 \n" ); document.write( "a=(5/2 - b/4)/6 \n" ); document.write( "a= 30/2 - 6b/4 \n" ); document.write( "a= 15 - 3b/2 ------ mark eqn 1. oks \n" ); document.write( "Now, this value of \"a\" we substitute it to the other eqn but first let simplify it, \n" ); document.write( "2a/3 - b/2=-2 ----- mark eqn 2 oks \n" ); document.write( "becomes, \n" ); document.write( "b/2=2a/3 +2 , and we subsitute \"a\" as shown in eqn 1 here. \n" ); document.write( "So, b/2= 2(15 -3b/2)/3 +2 \n" ); document.write( "b/2 = [2(30 - 3b)/2]/3 +2 \n" ); document.write( "b/2 (30-3b)/3 +2 \n" ); document.write( "b/2= (30-3b+6)/3 \n" ); document.write( "3b=60-6b+12 \n" ); document.write( "3b+9b=72 \n" ); document.write( "b=8 \n" ); document.write( "For \"a\", go back eqn 1: a=15 - 3(8)/2=15-12 \n" ); document.write( "a=3 \n" ); document.write( "In doubt? Simply go back to your eqn 2 to check, \n" ); document.write( "2(3)/3 - (8/2) =-2 \n" ); document.write( "2-4=-2 \n" ); document.write( "-2=-2, cool! \n" ); document.write( "Thank you, \n" ); document.write( "Jojo \n" ); document.write( " \n" ); document.write( " |