document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140973>Question 140973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 600. The length of the rectangle is 2 more than 3 times the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102633 by </B><A HREF=/tutors/aboutme.mpl?userid=jojo14344><B>jojo14344(1513)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jojo14344><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102633\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First and formost Perimeter of rectangle(P)=2(Length+Width)---------- eqn 1.<BR>\n" );
document.write( "But, there's a condition such being the Length 2 more than 3 times the Width.<BR>\n" );
document.write( "Therefore, the Length =2+(3)(Width) <BR>\n" );
document.write( "Going back eqn 1 and substituting the values:<BR>\n" );
document.write( "600=2(2+3W+W)<BR>\n" );
document.write( "600=2(2+4W)<BR>\n" );
document.write( "600=4+8W<BR>\n" );
document.write( "W=74.50<BR>\n" );
document.write( "Solving for L by reversing eqn 1.  becomes L=(P-2W)/2=(600-2*74.50)/2<BR>\n" );
document.write( "L=225.50<BR>\n" );
document.write( "Thank you,<BR>\n" );
document.write( "Jojo </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );