document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140917>Question 140917</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Calculate : 5x - 1/2 if 2x + 3 = 19 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102580 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102580\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+3=19<BR>\n" );
document.write( "2x=19-3<BR>\n" );
document.write( "2x=16<BR>\n" );
document.write( "x=16/2<BR>\n" );
document.write( "x=8 then:<BR>\n" );
document.write( "5x-1/2<BR>\n" );
document.write( "5*8-1/2<BR>\n" );
document.write( "40-1/2<BR>\n" );
document.write( "39 1/2 answer </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );