document.write( "Question 21358: ln(x-3)+ln(x)=ln(4) \n" ); document.write( "

Algebra.Com's Answer #10258 by venugopalramana(3286) $\"\"$ $\"About$

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ln(x-3)+ln(x)=ln(4)
\n" ); document.write( "USE LN X+LN Y=LN XY
\n" ); document.write( "LN X(X-3)=LN 4
\n" ); document.write( "TAKING ANTILOGS
\n" ); document.write( "X(X-3)=4
\n" ); document.write( "X^2-3X-4=0
\n" ); document.write( "X^2-4X+X-4=0
\n" ); document.write( "X(X-4)+1(X-4)=0
\n" ); document.write( "(X-4)(X+1)=0
\n" ); document.write( "X=4 OR -1...SINCE X=-1 GIVES L0G OF NEGATIVE NUMBERS WE DISCARD THAT (LOG OF A -VE NUMBER DOES NOT EXIST)SO X=4 \n" ); document.write( "

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