document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140923>Question 140923</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solving 6x^2+3x-18=0,using quadratic formula. would that be ax^+bx+c=0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102575 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6x^2+3x-18=0,using quadratic formula<BR>\n" );
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document.write( "Formula:<BR>\n" );
document.write( "x = [-b +- sqrt(b^2-4ac)]/(2a)<BR>\n" );
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document.write( "Your problem:<BR>\n" );
document.write( "x = [-3 +- sqrt(9-4*6*-18)]/12<BR>\n" );
document.write( "x = [-3 +- sqrt(441)]/12<BR>\n" );
document.write( "x = [-3 +- 21]/12<BR>\n" );
document.write( "x = (-3+21)/12 or x = (-3-21)/12<BR>\n" );
document.write( "x =(3/2) or x = -2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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