document.write( "Question 140923: Solving 6x^2+3x-18=0,using quadratic formula. would that be ax^+bx+c=0. \n" ); document.write( "

Algebra.Com's Answer #102574 by checkley77(12844) $\"\"$ $\"About$

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6x^2+3x-18=0
\n" ); document.write( "Following is the quadratic formula:
\n" ); document.write( " $\"x=%28-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29\"$
\n" ); document.write( "x=(-3+-sqrt[3^2-4*6*-18])/2*6
\n" ); document.write( "x=(9+-sqrt[9+432])/12
\n" ); document.write( "x=(9+-sqrt441)/12
\n" ); document.write( "x=(9+-21)/12
\n" ); document.write( "x=(3+21)/12
\n" ); document.write( "x=24/12
\n" ); document.write( "x=2 answer.
\n" ); document.write( "x=(3-21)/12
\n" ); document.write( "x=-18/12
\n" ); document.write( "x=-1.5 answer. \n" ); document.write( "

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