document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140737>Question 140737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An investor with interest compounded continuously doubled in 15yr. What is the interest rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102573 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102573\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=balance in account with principal P annual interest rate r and time in years t.<BR>\n" );
document.write( "Let P=1<BR>\n" );
document.write( "A=Pe^(rt)<BR>\n" );
document.write( "2=e^15r<BR>\n" );
document.write( "ln(2)=15r Take ln of both sides. Since the ln(e^15r)=15r<BR>\n" );
document.write( "r=ln(2)/15<BR>\n" );
document.write( "4.621...%<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );