document.write( "Question 140906: A sum of money was divided between man A, B and C in the ratio 1:2:3. Sadly, Man C died, and his money was divided between man A and B in the ratio 1:3. When this happened, man B had $2000 more than man A. What is their total sum?
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document.write( "(Answer = 4800 but i need to know how to do it) \n" );
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Algebra.Com's Answer #102570 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let amount A had be x, B had be 2x and C had be 3x. \n" ); document.write( "Let s be the sum. \n" ); document.write( "x+2x+3x=s \n" ); document.write( "since we must divide C's money in fourths, lets multiply the equation by 4. \n" ); document.write( "4x+8x+12x=4s \n" ); document.write( "7x+17x=4s A gets 3x and B gets 9x of C's 12x \n" ); document.write( "7x/4 + 17x/4 = s Divide each side by 4 \n" ); document.write( "17x/4 - 7x/4 = 2000 \n" ); document.write( "10x/4=2000 \n" ); document.write( "10x=8000 \n" ); document.write( "x=800 \n" ); document.write( "x+2x+3x=s \n" ); document.write( "800+1600+2400=$4800. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |