document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=140878>Question 140878</A>: <I><SPAN STYLE=\"word-break: break-all;\"> square inside a circle and i don't have the book<BR>\n" );
document.write( "if the area of the square is 144 find the area of the circle<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #102536 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=102536\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> square inside a circle and i don't have the book<BR>\n" );
document.write( "if the area of the square is 144 find the area of the circle<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "A side of the square is sqrt(144) = 12<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "The diagonal of the square is 12sqrt(2)<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "The diagonal is the diameter of the circle.<BR>\n" );
document.write( "(1/2) of the diagonal is the radius = 6sqrt(2)<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "Therefore the area of the circle = (pi)(6sqrt(2))^2 = 72pi<BR>\n" );
document.write( "===========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );