document.write( "Question 140754: Frederique is two years older than her brother. Twelve years ago she was twice as old as he was. how old are they now? \n" ); document.write( "

Algebra.Com's Answer #102519 by Fombitz(32388) $\"\"$ $\"About$

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Let Frederique's age be F and her brother's, B.
\n" ); document.write( "Right now,
\n" ); document.write( "1. $\"F=B%2B2\"$
\n" ); document.write( "12 years ago,
\n" ); document.write( "2. $\"F-12=2%28B-12%29\"$
\n" ); document.write( "Substitute 1 into 2 and solve for B.
\n" ); document.write( " $\"F-12=2%28B-12%29\"$
\n" ); document.write( " $\"%28B%2B2%29-12=2%28B-12%29\"$
\n" ); document.write( " $\"B%2B2-12=2B-24\"$
\n" ); document.write( " $\"B-10=2B-24\"$
\n" ); document.write( " $\"B-2B=-24%2B10\"$
\n" ); document.write( " $\"-B=-14\"$
\n" ); document.write( " $\"B=14\"$
\n" ); document.write( "Now that you have the brother's age, you can use a previous formula to find F.
\n" ); document.write( " $\"F=B%2B2\"$
\n" ); document.write( " $\"F=14%2B2\"$
\n" ); document.write( " $\"F=16\"$
\n" ); document.write( " \n" ); document.write( "

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